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mysql查找重复的数据

SELECT* , SUM(num) as '总数'FROMtd_textWHERENAME IN ( SELECT NAME FROM td_text GROUP BY NAME HAVING count(NAME) > 1 )GROUP BY `name`td_text 表数据: 执行sql后

select distinct biao.id from biao left outer join (select col1, col2 from biao group by col1, col2 having count(*) > 1) tmp on biao.col1 = tmp.col1 and biao.col2 = tmp.col2

select * from A where A.id=any(select Aid from B)试一下

select name from stu group by name;去重查名

下面以 sqlserver数据库为例进行说明。 select * from TableA where b in (select b from TableA group by b having count(b) > 1) 这样就列举出了b字段所有的重复数据,可以根据对应的行号,取得位于第几行。 如果要查询a字段或者c字段重复数据...

group的同时count(*), count(*)>1的都是有重复的。

SELECT*, count(t1.stu_id) AS ctFROMtable AS t1GROUP BYt1.stu_idHAVINGct > 1// table 替换为你的表名

操作方法如下: SELECT columname,COUNT(*) AS NUM FROM tablename GROUP BY columname ORDER BY NUM DESC LIMIT 1;

select * from 表 where n_id in (select s_name from 表 group by s_name,n_money,s_zhipiao,s_date,s_lixi having count(s_name)>1)

是同一列中重复出现的次数吧,试试: select distinct field ,count(*) from tbname group by field ;

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