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mysql查找重复的数据

SELECT* , SUM(num) as '总数'FROMtd_textWHERENAME IN ( SELECT NAME FROM td_text GROUP BY NAME HAVING count(NAME) > 1 )GROUP BY `name`td_text 表数据: 执行sql后

下面以 sqlserver数据库为例进行说明。 select * from TableA where b in (select b from TableA group by b having count(b) > 1) 这样就列举出了b字段所有的重复数据,可以根据对应的行号,取得位于第几行。 如果要查询a字段或者c字段重复数据...

在用select语句查询mysql数据库的时候,你可以加上distinct修饰符,这样就可以去掉好多重复的,比如 SELECT distinct(`lcontent`) FROM `caiji_ym_liuyan` 当然实际情况中的重复问题还有很多,需要自己的实际情况,构造相应的select语句。

select userid,username,userlevel from tb where userid not in(select userid from tb group by username,userlevel having count(1)=1)先找出没有重复的userid,然后过滤这些userid,其余的就是有重复的了

操作方法如下: SELECT columname,COUNT(*) AS NUM FROM tablename GROUP BY columname ORDER BY NUM DESC LIMIT 1;

数据 select a.* from t1 as a where i_time = (select max(i_time) from t1 where a.number=number) 查询结果

SELECT*, count(t1.stu_id) AS ctFROMtable AS t1GROUP BYt1.stu_idHAVINGct > 1// table 替换为你的表名

select * from A where A.id=any(select Aid from B)试一下

select 姓名列,count(1) as [重复次数] from 表名 group by 姓名列 having count(1)>=2 order by 重复次数 desc

select * from 表 where n_id in (select s_name from 表 group by s_name,n_money,s_zhipiao,s_date,s_lixi having count(s_name)>1)

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